(ab bc ca)^2 572279-Ab+bc+ca 2ad
Q 3 Am Is A Median Of A Triangle Trustudies Abc=1 => (abc)^2=1 a^2b^2c^22ab2bc2ca=1 => a^2b^2c^2abbcac3* (abbcac)=1 => a^2b^2c^2abbcac=0 => (ab)^2 (bc)^2 (ca)^2=0 Hence it follows, that a=b=c 35K views View upvotes Vivek Singh , Software Engineer at Tekion Answered 5 years ago Author has 236 answers and 6071K answer views It is very easy problemC ≤ ≤ ab=> cc ≤ ≤ c (ab) => c2 c 2 ≤ ≤ acbc (3) cộng vế với vế của (1); Ab+bc+ca 2ad